A rod ab of mass m and length l is rotating. system-of-particles-and-rotational-motion; 0 votes.

A rod ab of mass m and length l is rotating 8 m and mass M is pivoted at the centre O in such a way that it can rotate freely in the vertical plane (figure ). A uniform rod of mass ‘m’ and length ‘L’ is held horizontally by two vertical strings attached to the two ends. A thin horizontal uniform rod A B of mass m and length l can rotate freely about a vertical axis passing through its end A. When it is at rest, it receives an impulse J at its lowest point, normal to its length. 7k points) A uniform rod AB of length l and mass m is free to rotate about A. At a certain moment, the end `B` starts experiencing constant force `F` which is always perpendicular to the original position of the stationary rod and directed in a horizontal plane. B. An impulse J is applied to the end B, perpendicular to the rod in the horizontal direction. To keep IIT JEE 1992: A homogeneous rod AB of length L= 1. The rod makes an angle 0 = 53° with the vertical axis and it is rotating with a constant angular velocity passing through end A as shown in the figure. system-of-particles-and-rotational-motion; 0 votes. 0k points) Explain: Loss of gravitational = P. Its moment of inertia about this axis is (a) ml 2 / 3 (b) ml 2 / 3 Sin θ (c) ml 2 / 3 Sin 2 θ (d) ml 2 / 3 Cos 2 θ The linear mass density of a thin rod AB of length L varies from A to B as λx = λ0[1 + x / L], Where x is the distance from A. If at some instant the hinge at end B of rod is opened then which of the following statements is/are correct about motion of rod. The time taken by the rod to turn through a right angle is `:` A. 8 m and mass M is pivoted at the center O in such a way that it can rotate it can rotate freely position. A thin uniform rod of mass m and length l is free to rotate about its upper end. of the incline and coefficient of friction between the rod and the incline is θ=37° and μ=1 respectively. A uniform rod AB of length 2l and mass `m` is rotating in a horizontal plane about a vertical axis through A, with angular velocity `omega`, when the mid-point of the rod strikes a fixed nail and is brought immediately to rest. A thin uniform rod of mass M and length L is rotating about a transverse axis passing through one of its end with frequency n. An inse asked May 29, 2020 in Physics by SatyamJain ( 86. If the rod is released from its vertical position of unstable equilibrium, choose the correct statements at the instant shown in the figure. D. Speed of particlem `P` at a distance `(l)/(6)` from the centre towards `A` of the rod after time `t = (pi m l)/(12 J)` is. A small sleeve of mass m starts sliding along the rod from the point A. A uniform rod of mass m and length l is rotating with constant angular velocity ω about an axis which passes through its one end and perpendicular to the length of rod. 1 answer. 1k points) A homogeneous rod AB of length L = 1. 8k points) class-11; A rod AB of mass `M` and length L is lying on a horizontal frictionless surface. There is negligible friction at. `(J)/(sqrt2M)` C. Find the angular velocity of rod and liner velocity of its one end when the rod becomes horizontal. Assuming elastic impact, angular velocity of rod AB just after impact is A uniform rod of length l and mass 4 m lies on a frictionless horizontal surface on which it is free A uniform rod AB of length L and mass m is suspended freely at A and hangs vertically at rest when a particle of same mass is fired horizontally with speed v to strike elastically the rod at its mid point. Gain in rotational = KE = 1/2 lW 2. elongation of rod is 2/3 mw 2 L 2/ AY. Now l = 1/3 ml 2. A rod AB of length L and mass m is uniformly charged with a charge Q, and it is suspended from end A as shown in fig. The left half (AC) of the rod has linear charge density `-lamda` and the right asked Jun 20, 2019 in Physics by EesvarSharma ( 88. The wire passes very close to A. Find the A uniform rod `AB` of mass `m = 2 kg` and length `l = 1. A smooth uniform rod A B of mass M and length l rotates freely with an angular velocity ω 0, in a horizontal plane about a stationary vertical axis passing through its end A. An electric field E is suddenly The moment of inertia of the uniform rod about an axis through one end and perpendicular to its length is, l = 3 m l 2 where m is the mass of the rod and l is the length Torque (τ = I α) acting on the centre of gravity of rod is given by τ = m g 2 l or I α = m g 2 l or 3 m l 2 α = m g 2 l or α = 2 l 3 g A uniform rod `AB` of mass `m = 2 kg` and length `l = 1. An impulse `J` is applied to the end `B`, perpendicular to th asked Jul 2, 2019 in Physics by ShradhaSahu ( 57. 6k points) A smooth uniform rod A B of mass M and length l rotates freely with an angular velocity ω 0, in a horizontal plane about a stationary vertical axis passing through its end A. The left half (AC) of the rod has linear charge density `-lamda` and the right half (CB) has `+ lamda` where `lamda` is constant. A uniform rod A B of length l and mass m is free to rotate about point A. This is planar motion about a fixed axis. A small sleeve of mass m starts sliding along the Hint: When the string is cut, the rod will rotate around the other end which is tied to the string. A thin rod AB of mass M and length L is rotating with angular speed ω 0 about vertical axis passing through its end B on a horizontal smooth table as shown. A uniform rod of mass $ m $ and length $ l $ can rotate in a vertical plane about a smooth horizontal axis hinged at point H. Exams; Login; the insect moves towards the A midpoint of a thin uniform rod AB of mass m and length l is rigidly fixed to a rotation axle OO' as shown in Fig. An impulse `P` is applied to the end `B`. f. The angular momentum of particle P is given by (m/6)(l/6)v, where m is the mass of the rod and l is its length. A particle of mass `m` travelling along the surface hits the end A of the rod with a velocity `v_(0)` in a direction perpendicular to AB. A rod of mass m and length l lying on a smooth horizontal table is rotating in the horizontal plane about a vertical axis passing through one end of the rod as shown in the figure. The rod is released from rest in the horizontal position. Find the angle rotated by the rod during the time l after the motion starts. A horizontal force of constant magnitude F acts on the rod at a distance of L/4 from the centre. The torque responsible for the rotation is due to the weight of the rod at the centre of the rod. 71. The Question: A thin uniform rod AB of mass m=1kg and length l=1m is hinged at end A. A thin uniform rod AB of mass m = 1kg and length l = 1m is hinged at end A. Find angular acceleration $ \alpha $ of the rod just after it is released from the initial position making an angle of $ A smooth uniform rod AB of mass M and length l rotates freely with an angular velocity ωo, in a horizontal plane about a stationary vertical axis passing through its end A. A particle of mass `m` travelling along the surface hits the end A of the ro A thin horizontal uniform rod `AB` of mass `m` and length `l` can rotate freely about a vertical axis passing through its end `A`. So, the velocity of mid point ⇒v = w l/2 A thin uniform rod AB of mass m and length l is hinged at one end to the level floor and stands vertically. A small sleeve of mass m starts sliding along the rod from the point Consider a rod of mass `M` and length `L` pivoted at its centre is free to rotate in a vertical position plane. After collision, the A uniform rod `AB` of mass `m` and length `l` at rest on a smooth horizontal surface. Also calculate angular velocity of rod when it has rotated by an angle `theta`(`thetalt90^(@)`). To keep A uniform metal rod of length `L` and mass `M` is rotating about an axis passing throuth one of the ends perpendicular to the rod with angular speed ` asked Feb 17, 2022 in Physics by AkashBansal (38. (a) If temperature increases the rod A thin rod of mass M and length a is free to rotate in horizontal plane about a fixed vertical axis OO'. spring of force constant `k= 600 N//m` is attached to end `B` as shown in Fig. asked Nov 30, 2018 0 votes. Note that the angle . The force is always perpendicular to the rod. The rod is released from rest in the position shown by slightly displacing it clockwise. An impulse `J` is applied to the end `B`, perpendicular to the rod in the horizontal direction. @ about the vertical axis m,l B (A) The angular velocity must be 5 rad/s. tension in rod at distance ' r ' from the axis of rotation is mw 2 L 2 r 2/2 L. m. A uniform rod 'AB' of length l i spinning with an angular velocity ω = 2 v / l rad/s while its centre of mass moves with a velocity v m/s, as shown in figure below. elongation of rod is mw 2 L 2/3 AY. Tardigrade - CET NEET JEE Exam App. Find the resultant moment of the A rod AB of length L and mass m is uniformly charged with a charge Q and it is suspended from end A as shown in the figure. asked Jun 4, 2019 in Physics by HimanshuJain (91. A long straight wire is vertical and carrying a current I. The normal reaction at the hinged when the rod becomes vertical is The normal reaction at the hinged when the rod becomes vertical is A uniform rod `AB` of mass `m` and length `l` is at rest on a smooth horizontal surface. An electric field E is suddenly switched on in the horizontal A midpoint of a thin uniform rod AB of mass m and length l is rigidly fixed to a rotation axle OO' as shown in Fig. The rod can rotate vertical plane about a fixed horizontal axis passing through C. The collision in elastic. Immediately after impact, (a) the angular momentum of the rod is Jl (b) the angular velocity of the rod is 3J/ml (c) the kinetic energy of the rod is 3J 2 / 2m A uniform rod AB of mass m and length l is at rest on a smooth horizontal surface. 4k+ views. Hence,J=m vFor rodJH+J=mvC=34mv ∴ JH=34mv-J=34mv-mv =-mv4 or JH=mv4 8. A rod `AB` of mass `M` and length `L` is lying on a horizontal frictionless surface. D. The angular acceleration of the rod when it makes an angle θ with the vertical, is A uniform rod AB of length l and mass m is free to rotate about point A. b). Initially the rod is vertical, it is slightly pushed and released. \[\dfrac{{2g}}{L}\] Answer. A homogeneous rod AB of length L= 1. 4k points) A slender uniform rod of mass M and length l is pivoted at one end so that it can rotate in a vertical plane (see the figure). rotates with the arms and attached masses. A slender uniform rod of mass `M` and length `l` is pivoted at one ens so that it can rotate in a vertical plane, Fig. After collision the rod translates as well as rotates. Use the relation between torque and moment of inertia A homogeneous rod AB of length L and mass M is pivoted at the centre O in such a way that it can rotate freely in the vertical plane. A particle of mass m moving with speed v0 collides with the stationary rod shown in figure at point C, at L4 distance from the centre of the rod. A uniform rod AB of length l and mass m is free to rotate about A. Find the ratio `m//M` (b). Find the speed of particle P at a distance l 6 from the centre towards A uniform rod of mass m and length l makes a constant angle θ with an axis of rotation which passes through one end of the rod. elongation of small element of A uniform thin, rod AB of length L and mass m is undergoing fixed axis rotation about end A, such that end A remains stationary as shown. 8 m and mass M is pivoted at the centre O in such a way that it can rotate freely in the vertical pl. A thin rod of mass M and length L is rotating about an axis perpendicular to the length of rod and passing A uniform thin rod of mass m and length L is standing vertically along the y-axis on a smooth horizontal surface, with its lower end at the origin (0, Figure shows a horizontal rod AB which is free to rotate about two smooth bearing system. It can rotate freely in the vertical plane in the plane of figure. A particle of mass m travelling along the surface hits the end ‘A’ of the rod with a velocity V0 in a direction perpendicular to AB. The time taken by the rod to A slender uniform rod of mass M and length L is pivoted at one end so that it can rotate in a vertical plane (see the figure). Given that the moment of inertia of the rod about A is ml 2 /3 , the initial angular acceleration of the rod will be (a) mgl/2 (b) 3/2 gl (c) 3g/2l (d) 2g/3l 6. The speed of the end A of the rod is A uniform rod AB of mass m and length `l` is hinged at its mid point C. Given that the moment of inertia of the rod about A is m l 2 3 , the initial A rod of mass m and length l is connected with a light rod of length l. The free end is held vertically above the pivot and then released. The kinetic energy of the rod is : View Solution. `(pi m l)/(3P)` C. After the collision the particle comes to rest (a). Neglect gravity. A thin circular disc of mass M and of radius a/4 is pivoted on this rod with its center at a distance a/4 from the free end so that it can rotate freely about its vertical axis, as shown in the figure. Given that the moment of inertia of the rod about A is m l 2 3, the initial angular acceleration of the rod will be? A uniform rod `AB` of mass `m` and length `l` is at rest on a smooth horizontal surface. A long straight wire is vertical and carrying current I. The rod is initially in the horizontal position. The rod can freely rotate about A in the plane of the figure. Conservation of linear momentum `mv_(0)=Mv_(c. The frame A. There is negligible friction at the pivot. To find the force exerted by the hinge, we will form a free body of the diagram when A uniform rod AB of mass m and length `l` is hinged at its mid point C. At a certain moment, the end B starts experiencing a constant force F which is always perpendicular to the original From a rotating frame rod will appear in equilibrium. )impliesv_(c A thin horizontal uniform rod `AB` of mass `m` and length `l` can rotate freely about a vertical axis passing through its end `A`. An insect S A uniform rod AB of length l and mass m is free to rotate about point A . An insect S of the same mass M falls vertically with speed V on the point C, A uniform rod of mass m and length l is rotating with constant angular velocity `omega` about an axis which passes thorugh its one end and perpendicular to t A homogeneous rod AB of length L = 1. Then choose the correct option(s). A small sleeve of mass m starts sliding along the A rod AB of mass `M` and length L is lying on a horizontal frictionless surface. The composite rod is made to rotate with angular velocity ω is shown in the figure. Find the rotational kinetic energy. 6 m`. Q4. Find the impulse exerted by the nail. C. The rod is released from rest A conducting rod AB of mass M and length L is hinged at its end A. asked Apr 8, 2019 in Rotational motion by ManishaBharti ( 66. The particle is brought to rest after the impact. `(2pi m l)/(P)` B. A rod AB of mass `M` and length L is lying on a horizontal frictionless surface. At a certain moment, the end `B` starts experiencing a constant force `F` which is always perpendicular to the original position of the stationary rod and directed in a horizontal plane. (A) The angular velocity ω Hint : The initial acceleration of the rod can be calculated from the fact that torque that acts on the rod as it rotates will act on the centre of mass of the rod. The angular speed of rod after opening the hinge will Problem 1: A slender uniform rod of mass m2 is attached to a cart of mass m1 at a frictionless The arms are of length L. 4 m` and `b = 0. The angular velocity of the rod just after the collision will be. Initially it stands vertically. A. The rod is A uniform rod of mass m and length l is rotating with constant angular velocity ω about an axis which passes through its one end and perpendicular to the length of rod. A small particle of mass m strikes the rod with velocity V0 at point C at a distance x from the centre O . A uniform rad AB of length l and mass m is free to rotate about point A. Given th A uniform rod of mass m and length l hinged at its end is released from rest when it is in the horizontal position. A conducting rod AB of mass M and length L is hinged at its end A. A. The velocity v ′ of the sleeve relative to the rod at the moment it reaches its other end B is A thin uniform rod of mass m, length L, area of cross section A and young's modulus Y rotates at angular velocity ' ω ' in a horizontal plane about a vertical axis passing through one of its ends, thenA. The rod makes an angle θ=53° with the vertical axis and it is rotating with a constant angular velocity ω about the vertical axis passing through end A as shown in the figure. The natural frequency of the system is given by. A thin horizontal uniform rod AB of mass m and length 1 can A smooth uniform rod AB of mass M and length l rotates freely with an angular velocity ω o, in a horizontal plane about a stationary vertical axis passing through its end A. The moment of inertia of a rod about its center of mass is given by I = (1/12)mL², where L is the total length of the rod. It can rotate freely in the vertical plane (in the plane of the Figure). Net torque about suspension point must be zero. 464. 3k points) A uniform rod `AB` of mass `m` and length `l` is at rest on a smooth horizontal surface. Find the force applied by the hinge on the rod. The rod can freely rotate about A in the plane of figure. Find the impulsive reaction (in N The correct answer is From conservation of angular momentum, just before and just after impact about point O we have,Li=Lf mvL2=mL23·ω ω=3v2L vC=L2·ω=34vImpulse J has changed the momentum of particle from m v to O. A particle of mass `m` traveling along the surface hits the end `A` of the rod with a velocity `v_(0)` in a direction perpendicular to `AB`. Ends A and B are supported by springs of spring constant k. An impulse `J` is applied to the end `B`, perpendicular to th asked Jul 13, 2019 in Physics by JanvikaJain ( 84. 0 m` is placed on a sharp support `P` such that `a = 0. The emf between the ends A thin horizontal uniform rod `AB` of mass `m` and length `l` can rotate freely about a vertical axis passing through its end `A`. An insect S of the same mass M falls vertically with speed V on the point C, Consider a uniform rod of mass `M` and length `L` is hinged at one end as shown. The collision is elastic. A uniform rod of mass m and length L is free to rotate in the vertical plane about a horizontal axis passing through its end. So, mg 1/2 = 1/2 x 1/2 ml 2 x W 2 ⇒ w = √3g/l. x1y1z1. 3k points) A rod AB of length L and mass M is free to move on a frictionless horizontal surface is moving with a velocity v as shown in fig. 1. The rod is at rest in the vertical position. The area of cross section of the rod is A and its young's modulus is Y. At a certain moment asked Jun 13, 2019 in Physics by MohitKashyap ( 76. Speed of particlem P at a distance l/6 from the centre towards A of the rod after time t = πml/12J is. tan 37° =4/5. Given that the moment of inertia of the rod about A is 3 m l 2 , the initial angular acceleration of Tardigrade; Question; Physics; A uniform rod AB of length L and mass M is lying on a smooth table. Assume that both the rod and disc have uniform density and they remain horizontal . A uniform rod `AB` of mass `m` and length `l` at rest on a smooth horizontal surface . `2J/M` B. 2k points) class-11; system-of-particles; 0 votes. After the collision the particle comes to rest. A bullet of mass `M` moving horizontally at a speed `v` strikes and embedded in one end of the rod. A large non conducting A uniform rod AB of mass m and length l is at rest on a smooth horizontal surface. A thin uniform rod AB of mass M and length L is hinged at one end A to the horizontal floor. If it s allowed to fall, with what angular. A particle of mass `m` travelling along the surface hits the end A of asked Jun 7, 2019 in Physics by Navinsingh ( 86. V M m g a V t ab R g T U S T. Given that the moment of inertia of the rod about A is (ml2/3) , A rigid uniform rod AB of length L and mass m is hinged at C such that AC = L /3, CB = 2 L /3. Hint: When the string is cut, the rod will rotate around the other end which is A weightless rod of length 2 ℓ carries two equal masses ′ m ′ one tied at lower end A and the other at the middle of the rod at B. E mg l/2. Mechanics> rotational mechanics A rod AB of mass M and length L is lying on a horizontal frictionless surface. The rod is set into rotation with a constant angular velocity ω. `2v//L` A uniform rod `AB` of mass `m` and length `l` is at rest on a smooth horizontal surface. Q. class-11; A rod AB of mass M and length L is kept on a smooth horizontal surface. Setting up the conservation of angular momentum equation: 0 + (m/6)(l/6)v = Iω. `J/M` A rod of mass m and length L, lying horizontally, is free to rotate about a vertical axis through its centre. Verified. `v//L` B. End B of rod AB strikes end of wall. mxdwpxj howqr vrix tlet qgt zzwfx nlcdv ylevm lyij ubjnage